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The force exerted by a pulley is the sum of the tension and the force of gravity. Since a pulley is used to lift something, the force is negative. The tables show the tension, T(m), and the force of gravity, G(m), for objects of various masses, m in grams, all accelerating upward at 2.5 m/s2.

The force of the rope is equal to the negative of the tension on the rope and the force of gravity.
Which table shows the values when combining the functions to find the force of the rope?

The force exerted by a pulley is the sum of the tension and the force of gravity. Since-example-1
User Froston
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5.6k points

2 Answers

4 votes

Answer:

B

Explanation:

User Eric Hartford
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5.2k points
7 votes

Answer:

B

Explanation:

To answer this question, we can just pick a couple of points and see which table gives the correct values.

Test Value 1)

Let's let m be 0.5.

So, our output will be:


-(T(0.5)+G(0.5))

From our original tables, we know that T(0.5) is 1.25 and G(0.5) is 4.9. So:


=-(1.25+4.9)

Add:


=-6.15

So, when m is 0.5, our output should be -6.15.

The only choice that does this is B. So, B is our correct answer!

However, let's do another test point just to confirm.

Test Value 2)

Let's let m be 1.2.

So, our output will be:


-(T(1.2)+G(1.2))

From our original table, we know that T(1.2) is 3 and G(1.2) is 11.76. So:


=-(3+11.76)

Add:


=-14.76

The only choice that does this is B. So, we are confident that B is our answer.

And we're done!

User Bug
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5.6k points