Question

A projectile is thrown upwards from an initial height of 1584 feet so that it's distance above the ground after t seconds is modeled by the given function.

h(t)=-16t^2+480t+1584.

what is the maximum height it will reach?​

Answer 1

• 5184 ft

Explanation:

Given

A quadratic function

• h(t)= -16t^2+480t+1584.

Its maximum is its vertex

Vertex formula for ax^2 + bx + c is

• x = -b/2a

Applying this to our function

• t = -480/2(-16) = 15

Maximum height is reached after 15 seconds and is

• h(15) = -16*15^2 + 480*15 + 1584 = 5184 ft