Question

4. Solve the following heat flow problem, being sure to show all your work (you may either type your

work or insert an image): Find the specific heat of 402 grams of graphite that absorbs 1136) of heat
energy as it changes temperature from 26°C to 30°C.
Answer should be 0.7J/gC

Answer 1

0.70 J/g.°C

Step-by-step explanation:

Step 1: Given data

• Mass of graphite (m): 402 g

• Heat absorbed (Q): 1136 J

• Initial temperature: 26°C

• Final temperature: 30 °C

• Specific heat of graphite (c): ?

Step 2: Calculate the specific heat of graphite

We will use the following expression.

Q = c × m × ΔT

c = Q / m × ΔT

c = 1136 J / 402 g × (30°C - 26°C)

c = 0.70 J/g.°C