Question

Below is a diagram of Hillcrest High School. The english and math buildings are congruent rectangles. The art building is a square. The total perimeter of Hillcrest High school’s building is 1,718 feet. Find the value of x. Find the missing perimeters for the buildings.

1. Find the value of x.
2. Find the missing perimeters for the buildings.
3. What is the area of the English building? (plug in your x value!)

Answer 1

Answer/Step-by-step explanation:

1. Perimeter of the building = sum of all the length of the outer borders surrounding the building = 1,718 ft

Thus:

4x - 6 + 2x + 3x + 2(3x + 4) + 3x + 2x + x + x + x + 2x + 4x - 6 + 2(3x + 4) + 4x - 6 + 3x = 1,718

Open the Parentheses

4x - 6 + 2x + 3x + 6x + 8 + 3x + 2x + x + x + x + 2x + 4x - 6 + 6x + 8 + 4x - 6 + 3x = 1,718

Combine like terms

42x - 2 = 1,718

42x = 1,718 + 2

42x = 1,720

x ≈ 41

2. Missing perimeter of Building = 2x + 2x + 4x - 6

Simplify

= 8x - 6

Plug in the value of x

= 8(41) - 6

= 322 ft

3. Area of English Building = length * width

= (4x - 6 + 2x)(3x)

Simplify

= (6x - 6)(3x)

Plug in the value of x

= (6(41) - 6)(3(41))

= (246 - 6)(123)

= (240)(123)

= 29,520 ft²