Question

If I have 21,000 mL of gas at a temperature of 870C and a pressure of 101 atm, what will be the pressure of the gas if I raise the temperature to 1040C and decrease the volume to 15 liters?

Answer 1

We have,

Initial volume is V

1

​

Initial temprature is T

1

​

=75

0

C

Initial pressure is P

1

​

So, final temprature is T

2

​

=273+75=348K

V

2

​

=V

1

​

−

100

15

​

V

1

​

=

100

85V

1

​

​

Applying the gas formula,

T

1

​

P

1

​

V

1

​

​

=

T

2

​

P

2

​

V

2

​

​

348

P

1

​

V

1

​

​

=

T

2

​

×100

2P

1

​

×85V

1

​

​

T

2

​

=

100

2×85×348

​

T

2

​

=591.6K