Question

The number of atoms in 2.0 moles of B is

Answer 1

Given :

Number of moles of boron (B) = 2

To Find :

We have to find number of atoms present in the given amount of boron
`.`

Solution :

➤ We know that 1 mole of substance contains 6.022×10²³ particles (atoms/molecules).

• Avogadro's no. = 6.022 × 10²³

★ Number of atoms present in B :

⭆ N = n ×
`\sf{N_A}`

• N denotes number of atoms
• n denotes mole number
• 
  `\sf{N_A}` denotes avogadro's number

⭆ N = 2 × 6.022 × 10²³

⭆ N = 12.044 × 10²³

⭆ N = 1.2 × 10²⁴

Hope It Helps!

Answer 2

The answer is

1.204 × 10²⁴ atoms of B

Step-by-step explanation:

To find the number of entities of a substance given it's number of moles we use the formula

N = n × L

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question

n = 2.0 moles

We have

N = 2 × 6.02 × 10²³

We have the final answer as

1.204 × 10²⁴ atoms of B

Hope this helps you