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9e^2x - 30e^x + 25 = 0



Please I need a step by step solution urgently ​

1 Answer

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Answer:

Here you go

Explanation:

The first term is, 9e2 its coefficient is 9 .

The middle term is, +30e its coefficient is 30 .

The last term, "the constant", is +25

Step-1 : Multiply the coefficient of the first term by the constant 9 • 25 = 225

Step-2 : Find two factors of 225 whose sum equals the coefficient of the middle term, which is 30 .

15 + 15 = 30 That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, 15 and 15

9e2 + 15e + 15e + 25

Step-4 : Add up the first 2 terms, pulling out like factors :

3e • (3e+5)

Add up the last 2 terms, pulling out common factors :

5 • (3e+5)

Step-5 : Add up the four terms of step 4 :

(3e+5) • (3e+5)

Which is the desired factorization

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