Question

How many moles are in 1.93x1023 particles of Na3PO4?

Answer 1

No. of particles of Na₃PO₄ = 1.93×10²³

We have to find number of moles of the given compound
`.`

Number of moles cam be found by using this formula :

`\bigstar\:\boxed{\bf{\purple{n=(N)/(N_A)}}}`

• n denotes number of moles
• N denotes number of particles
• 
  `\sf{N_A}`denotes avogadro's constant

We know that,

• 
  `\bf{N_A}` = 6.022×10²³

★ Calculation :

➠ n = N/
`\sf{N_A}`

➠ n = (1.93×10²³)/(6.022×10²³)

➠ n = 0.32 moles

★ Explore More :

• n = weight / Molar mass
• n = volume / 22.4

Hope It Helps!

Answer 2

The answer is 0.32 moles

Step-by-step explanation:

To find the number of moles given the number of entities we use the formula

`n = (N)/(L) \\`

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question

N = 1.93 × 10²³ particles

We have

`n = \frac{1.93 * {10}^(23) }{6.02 * {10}^(23 ) } \\ = 0.320598006...`

We have the final answer as

0.32 moles

Hope this helps you