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How many mols of water are produced from 88.0g of methane?

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Answer:

C3H8(g) + 5O2(g) → 3CO2(g) + 4H2O(g)

88.0g ………………….. ………………………..?g

88.0g C3H8 x (1 mol C3H8 / 44.0g C3H8) x (4 mol H2O / 1 mol C3H8) x (18.0g H2O / 1 mol H2O) = 144g H2O

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