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-5t^2+10t+22 does the ball reach a height of 35m

User Siva Gopal
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1 Answer

6 votes

Answer:

Explanation:

35=-5t²+10t+22

5t²-10t+13=0

disc =b²-4ac=(-10)²-4×5×13=100-260=-160<0

t is imaginary.

So ball never reaches a height of 35 m

User Dskim
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