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Find an equation of the circle that has center (-3, -6) and passes through (0, 1).

User Majjam
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Answer:

Explanation:

General equation for a circle (x - a)² + (y - b)² = r² with (a,b) represents the center, (x,y) represents one of the points lie on the circle, and r represents the radius Determine r² by substituting the points into the general equation (x - a)² + (y - b)² = r² (5 - (-1))² + (-4 - 2)² = r² (5 + 1)² + (-6)² = r² 6² + 36 = r² 36 + 36 = r² 72 = r² Determine the equation of the circle (x - a)² + (y - b)² = r² (x - (-1))² + (y - 2)² = 72 (x + 1)² + (y - 2)² = 72 (This is the equation of the circle)

User Husker Jeff
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