Question

Find the area and perimeter of a rectangle if the length is (x+7) and the width is (x+3).

Answer 1

`l = (x + 3) \\ b = (x + 7)`

Area:

`= l * b \\ = (x + 3)(x + 7) \\ = x(x + 7) + 3(x + 7) \\ = {x}^(2) + 7x + 3x + 21 \\ = {x}^(2) + 10x + 21`

Perimeter:

`= 2(l + b) \\ = 2((x + 3) + (x + 7)) \\ = 2(x + 3 + x + 7) \\ = 2(2x + 10) \\ = 4x + 20`

Answer 2

`\sf Length\:=\:(x+7) \\\\\sf</p><p>Breadth\:=\:(x+3) \\\\\sf</p><p></p><p>Area= Length\: x\: Breadth \\\\\sf</p><p>=(x+3)(x+7) \\\\\sf</p><p>=x^2+7x+3x+21 \\\\\sf</p><p>=x^2+10x+21 \\\\\sf</p><p>\boxed{Area=x^2+10x+21} \\\\ \\\\\sf</p><p></p><p>Now, \:Perimeter\:=\: 2x(length +breadth) \\\\\sf</p><p>=2(2x+10) \\\\\sf</p><p>=4x+20 \\\\\sf</p><p>\boxed{Perimeter=4x+20}`