Answer:
47.4 ft/s
Step-by-step explanation:
Using v² = u² - 2gs where u = initial vertical velocity of ball = 100sin30, v = final vertical velocity of ball at the time it was caught by the fielder, g = acceleration due to gravity = 32 ft/s² and s = vertical displacement = y₂ - y₁, y₁ = 3 ft and y₂ = 7 ft. s = y₂ - y₁ = 7 - 3 = 4 ft
Substituting these values into the equation, we have
v² = u² - 2gs
v² = (100sin30)² - 2 × 32ft/s² × 4 ft
v² = (100sin30 ft/s)² - 256 ft²/s²
v² = (50 ft/s)² - 256 ft²/s²
v² = 2500 ft²/s² - 256 ft²/s²
v² = 2244 ft²/s²
v = √2244 ft²/s²
v = 47.37 ft/s
v ≅ 47.4 ft/s
So, the velocity of the ball relative to the fielder at the instant the catch is made is 47.4 ft/s.