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Christine has always been weak in mathematics. Based on her performance prior to the final exam in Calculus, there is a 42% chance that she will fail the course if she does not have a tutor. With a tutor, her probability of failing decreases to 12%. There is only a 52% chance that she will find a tutor at such short notice.

User Malax
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Complete Question

Christine has always been weak in mathematics. Based on her performance prior to the final exam in Calculus, there is a 42% chance that she will fail the course if she does not have a tutor. With a tutor, her probability of failing decreases to 12%. There is only a 52% chance that she will find a tutor at such short notice

a What is the probability that Christine fails the course

b Christine ends up failing the course. What is the probability that she had found a tutor? (Round your answer to 4 decimal places.) Probability

Answer:

a


P(F) =   0.264

b


P(T | F ) = 0.23636

Explanation:

From the question we are told that

The probability that Christine will fail the course if she does not have a tutor is
P(F| T') = 0.42

The probability that Christine will fail the course if she has a tutor is
P(F| T) = 0.12

The probability that she will find a tutor is
P(T) = 0.52

Generally the probability that she will not find a tutor is


P(T') = 1 - 0.52

=>
P(T') = 0.48

Generally the probability of failing the course is


P(F) = P(F \ n \ T) + P(F \ n \ T')

=>
P(F) = P(F| T) * P(T) + P(A | T') * P(T')

=>
P(F) = 0.12 * 0.52 + 0.42* 0.48

=>
P(F) = 0.264

Generally if Christine ends up failing the course the probability that she had found a tutor? (Round your answer to 4 decimal places.) Probability is mathematically represented as


P(T | F ) = ( P(F | T) * P(T))/( P(F))

=>
P(T | F ) = ( 0.12 * 0.52)/( 0.264)

=>
P(T | F ) = 0.23636

User Vvavepacket
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