Answer:
See explanation
Step-by-step explanation:
When the bromine free radical attacks 2,3-dimethylbutane, two free radicals may result. One of them is primary (formed by attack on then end -CH3 group) the other is secondary.
Recall that the order of stability of free radicals is tertiary > secondary > primary > methyl.
Hence the secondary free radical is more thermodynamically stable hence it is the major free radical formed in the first propagation step.