Answer:
a) vₓ = 100 + 7.07 = 107.07 knot (East) , v_{y} = 7.07 knot (North)
b) v_wind_ North = 0 , v_wind_West = 61.12 knot (West)
Step-by-step explanation:
a) This is a vector velocity addition problem, they tell us that the plane goes East at 100 Knots and the wind goes North East at 10 Knots
the components ask the total speed of the plane.
For this we decompose the wind speed
cos 45 = v₂ₓ / V₂
sin 45 =
/ v₂
v₂ₓ = v₂ cos 45
v_{2y} = v₂ sin 45
v₂ₓ = 10 cos 45 = 7.07 m / s
v_{2y} = 10 sin45 = 7.07 m / s
the speed of the plane is
vₓ = v_plane + v₂ₓ
v_{y} = v_{2y}
vₓ = 100 + 7.07 = 107.07 knot (East)
v_{y} = 7.07 knot (North)
speed is
v = (107.07 i ^ + 7.07 j ^) knot
b) Estimated time for Target VOR t = 10 min
for a time of t = 10 min and 15 s, it is at a distance of d = 300 m from the VOR in an easterly direction
find the average speed of time on the ride
in the North direction there is no deviation so the average wind speed is zero
v_wind_ North = 0
In the east direction
as the estimated time was 10 min and the real time for the distance is 10 min 15 s
the time difference is t = 15 s to travel d = 300 m
with these data we can calculate the speed of the plane
v = x / t
v = 300/15
v = 20 m / s
let's reduce this speed to knot
v_real = 20 m / s (1knot / 0.5144 m / s) = 38.88 knots
therefore the wind speed is
v_tral = v_plane + v_wind_Este
v_wind_Este = v_real - v_avión
v_wind_Este = 38.88 - 100
v_wind_Este = -61.12 knot
the negative sign indicates that the wind is going west
v_wind_West = 61.12 knot (West)
3)
* The compass is not calibrated, to correct the magnetic deviation, therefore it gives an appreciable error in the direction
* The wind speed is taken when leaving, but there is no constant monitoring, so a change in direction or wind speed in the trajectory can significantly affect the results.
* The aircraft may noir throughout the trajectory at level, due to pitch errors