Answer:
4477381.7 calories/pound
Step-by-step explanation:
It is given that,
When a candle burns it produced 41,300 Joules per 1 gram.
We need to convert it into calories per pound.
We know that,
1 cal = 4.184 J
⇒ 1 J = (1/4.184) cal
1 pound = 453.592 grams
⇒1 g = (1/453.592) pounds
Now,
![41300\ \text{Joules per gram}=\frac{41300\ \text{Joules}}{\text{gram}}\\\\=41300* \frac{(1)/(4.184)\ \text{calories}}{(1)/(453.592)\ \text{gram}}\\\\=4477381.7\ \text{calories/pound}](https://img.qammunity.org/2021/formulas/chemistry/high-school/8k79f6c5i8j1gaosi70o6pxsa2c6xdxctz.png)
Hence, 41,300 Joules/gram = 4477381.7 calories/pound.