Question

A student read that a block has a density of .70g/cm^3. When she tested this she got .63g/cm^3. What is her percent error

Answer 1

The answer is 10 %

Step-by-step explanation:

The percentage error of a certain measurement can be found by using the formula

`P(\%) = (error)/(actual \: \: number) * 100\% \\`

From the question

actual density = 0.7 g/cm³

error = 0.7 - 0.63 = 0.07

So we have

`p(\%) = (0.07)/(0.7) * 100 \\ = 10`

We have the final answer as

10%

Hope this helps you