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Find three consecutive odd integers such that the sum of the smallest number and middle number is 27 less than 3 times the largest number

User TFKyle
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1 Answer

3 votes

Answer:

x+(x+2) = 3(x+4) -27

Explanation:

Let's look at all the parts.

Consecutive odd integers... that means that if x is the first one, then x+2 will be the next largest one, and x+4 will be the largest one. So if x is 5, x+2 is 7, and x+4 is 9.

User Anton Hansson
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