Question

each term of a sequence is 2 more than the previous term. if the third term is 8 find the first five terms of the sequence

Answer 1

Explanation:

T3=8

8=a+2d

where a is first term ,d is common ratio

8=a+2(2)

8=a+4

a=8-4

a=4

first term T1 is 4

T2=a+d

T2=4+2

T2=6

T4=a+3d

T4=4+3(2)

T4=4+6

T4=10

T5=a+4d

T5=2+4(2)

T5=4+8

T5=12

4,6,8,10,12