Question

6≥−6(a+2) solve and find the awnser

Answer 1

-3<=a

Explanation:

1. Get the -6 away, so multiply everything by -6. 6*-6 >= -6*-6(a+2)

2. This becomes -1 <= a+2 Since if you multiply or divide anything by a negative number, you have to reverse the inequality sign.

3. Subtract 2 to get a by itself -1-2 >= a

4. This becomes -3 >= a which is the right answer.

(Just so you know >= and <= means less than or equal to and more than or equal to.)

Answer 2

`- 3 \geqslant a`

Explanation:

`6 \geqslant - 6(a + 2)`

distribute -6 inside the parentheses

`6 \geqslant - 6a - 12`

add 12 to both sides

`18 \geqslant - 6a`

divide by -6 to isolate the variable

`- 3 \geqslant a`