Question

Using the formula Q = m x ^T x Cp, solve for energy, and round your answer to the correct number of sig figs and show all work:

1) How much heat is absorbed by 1210. g water (Cp = 4.184 J/g*C) when it is heated from 20*C to 45*C

Answer 1

Q = 126.5 kJ

Step-by-step explanation:

Given that,

Mass, m = 1210 g

Specific heat of water, c = 4.184 J/g°C

Initial temperature,
`T_i=20^(\circ) C`

Final temperature,
`T_f=45^(\circ) C`

We need to find the heat absorbed by water. The formula that is used to find the heat absorbed is given by :

`Q=mc\Delta T`

Putting all the values in it we get :

`Q=1210\ g* 4.184\ J/g^(\circ) C* (45-20)^(\circ) C\\Q=126566\ J\\\\\text{or}\\\\Q=126.5\ kJ`

So, the amount of heat absorbed is 126.5 kJ.