Question

HELLLLLLLLp i dum please help me

Answer 1

B

Explanation:

(6
`x^(5)`z)^3

6^3 is 226

*(x^2)^3= x^6 (5*3= 15)

*when there are exponents being raised to a power, the exponents are multiplied

**(z^1)^3= z^3 (3*1= 3)

** all numbers are raised to the 1st power (unless otherwise noted x^2, 5^4 2^2, etc)

So the top would end up being 226x^6z^3

Now, since this number is over 4x^4z^2, you need to divide 226x^15z^3 by 4x^4z^2

**divide like terms**

226/4= 54

***x^15/ x^4= x^x^11

*** when you divide exponents, you subtract the bottom number from the top, in this case:

15-4

that equalls 11

So x^11

you do the same for z:

z^3/z^2= z^1 or z (3-2=1 )

You put it all together and you end up with

54x^11z

******** If there are any mistakes I'm really sorry!!******