Question

The specific heat capacity of water is 4,200 J/kg °C.

Calculate the thermal energy that must be
absorbed by 1.4 kg of water to increase its
temperature by 25 °C.

help TvT​

Answer 1

It’s a simple formula
Q = m*c*Δt
M being mass
C being specific heat
Δt being change in temperature

Q = (1.4kg)(4,200J/kg*C)(25C)
Kilograms and Celsius cancels and you get 147,000 Jules aka 1.47 x 10^5 J