Question

Help please and fast!​

Answer 1

1

Explanation:

`[(3a^(-2) b^6)/(2a^(-1)b^5)] ^(2) \\=[1.5 a^(-2-(-1)) b^(6-5)]^2\\=[1.5a^(-2+1)b]^2\\=[1.5a^(-1)b]^2\\\\Substituting\ a=3,b=-2, we\ get,\\=[1.5*3^(-1)*-2]^2\\=[1.5*1/3*-2]^2\\=[1/2*-2]^2\\=[-1]^2\\=1`

Answer 2

= [3x3^-2x(-2)^6/2x3^-1x(-2)^5]^2 = 1