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Equation 1: 3x - 5y = 4
equation 2: -2x + 6y= 18

User Arad
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Final answer:

To solve the system of equations 3x - 5y = 4 and -2x + 6y = 18, multiply Equation 1 by 2 and Equation 2 by 3 to eliminate the x term. Add the resulting equations and solve for y. Substitute the value of y back into the equations to solve for x. The solution is x = 14.25 and y = 7.75.

Step-by-step explanation:

The given equations are:

Equation 1: 3x - 5y = 4

Equation 2: -2x + 6y = 18

To solve this system of equations, we can use the method of substitution or elimination. Let's use the method of elimination:

Multiply Equation 1 by 2 and Equation 2 by 3 to eliminate the x term:

2(3x - 5y) = 2(4) --> 6x - 10y = 8

3(-2x + 6y) = 3(18) --> -6x + 18y = 54

Add the resulting equations:

(6x - 10y) + (-6x + 18y) = 8 + 54

-10y + 18y = 62

8y = 62

Solve for y:

y = 62/8 = 7.75

Substitute the value of y back into Equation 1 or Equation 2 to solve for x:

Using Equation 1:

3x - 5(7.75) = 4

3x - 38.75 = 4

3x = 42.75

x = 42.75/3 = 14.25

The solution to the system of equations is x = 14.25 and y = 7.75.

User Muesli
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