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What is the slope of the line with equation y-3=-1/2 (x-2)

User Rickard
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Given parameters:

Equation of the straight line;

y - 3 =
(-1)/(2)(x -2)

We can determine the slope of any straight line from the equation of such lines.

Generally, a straight line has the formula;

y = mx + C

where y is the y-axis coordinate and x is the x-axis coordinate

m is the slope and c is the y-axis intercept

Now let us express the given equation in this format;

y - 3 =
(-1)/(2)(x - 2)

Multiply both sides by 2;

2(y - 3) = -1(x -2)

2y -6 = -x + 2

Rearrange to the form y = mx + c

2y = -x + 2 + 6

2y = -x + 8

divide by 2;

y =
(-1)/(2)x + 4

y = mx + c

the slope is m and it is equal to
(-1)/(2)

User Out
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