Question

The lifespans of lions in a particular zoo are normally distributed. The average lion lives 1 2 . 5 12.512, point, 5 years; the standard deviation is 2 . 4 2.42, point, 4 years. Use the empirical rule ( 6 8 − 9 5 − 9 9 . 7 % ) (68−95−99.7%)left parenthesis, 68, minus, 95, minus, 99, point, 7, percent, right parenthesis to estimate the probability of a lion living less than 1 0 . 1 10.110, point, 1 years.

Answer 1

Probability of a line living less than 10.1 years is 16%.

Explanation:

It is given that, lifespan of lines in a particular zoo are normally distributed.

Mean =12.5

standard deviation= 2.4

We need to find the P(x<10.1)

So, let's use Empirical rule.

mean± standard deviation = 68%

Mean±2 standard deviation= 95%

mean ±3 standard deviation=99.7%

Now, let's use this rule to solve our problem.↑