Question

The scores of an eighth-grade math test have a normal distribution with a mean u = 83 and a standard deviation o = 5. If

Din's test score was 92, which expression would she write to find the z-score of her test score?

OZ. z=92-83/83

z=83-91/5

z=92-83/5

z=5-83/92

Answer 1

C on EDG

Explanation:

Answer 2

z=92-83/5

Explanation:

The formula for calculating a z-score is given as:

z = (x-μ)/σ,

where

x is the raw score

μ is the population mean

σ is the population standard deviation.

Where: from the question

x is the raw score = 92

μ is the population mean = 83

σ is the population standard deviation = 5

z = 92 - 83/5

Therefore, expression would she write to find the z-score of her test score is

z = 92 - 83/5