Question

What is an equation of the line that passes through the points (6, -5) and (3,0)?

Answer 1

Explanation:

Hey there!

The equation of a st.line passing through points (6,-5) and (3,0) is;

`(y - y1) = (y2 - y1)/(x2 - x1) (x - x1)`

[Using double point formula]

Now, Put all values,

`(y + 5) = (0 + 5)/(3 - 6) (x - 6)`

Simplify it to get equation.

`(y + 5) = - (5)/(3) (x - 6)`

`3(y + 5) = - 5(x - 6)`

`3y + 15 = - 5x + 30`

`5x + 3y + 15 - 30 = 0`

`5x + 3y - 15 = 0`

Therefore the required equation is 5x + 3y - 15 = 0.

Hope it helps...

Answer 2

y = -5/3x + 5

Explanation:

The formula for the equation of a line is :

y - y1 = m (x-x1)

m is the gradient

finding the gradient

formula

`(y2-y1)/(x2-x1) \\\\`

= (0--5)/ (3-6)

=5 / -3

gradient = - 5/3

inserting the values in formula for the equation of a line

y - y1 = m (x-x1)

y - -5 = -5/3 (x - 6 )

y + 5 = -5/3 x + 10

y = -5/3x + 10 - 5

y = -5/3x + 5