Question

What is the midpoint of (-7,-9) (6,3)

Answer 1

Let the first term of both the terms be
`\: \sf \: x _1 \: \: \& \: \: x _2` and last term be
`\: \sf \: y _1 \: \: \& \: \: y_2\\`

Now, by using the mid point formula to find the mid point of the segment -

`\\ \sf \bigg( (x_1 + x_2)/(2) , \: (y_1 + y_2)/(2) \bigg) \\`

Now, by substituting the values of both x and y -

`\\ \sf \bigg( ( - 7 + 6)/(2) , \: ( - 9 + 3)/(2) \bigg) \\`

Adding -7 and 6 -

`\\ \sf \bigg( ( - 1)/(2) , ( - 9 + 3)/(2) \bigg) \\`

Now, move the negative in front of the fraction -

`\\ \sf \bigg( ( - 1)/(2) , ( - 6)/(2) \bigg) \\ \\ \\ \sf \bigg( ( - 1)/(2) , - 3\bigg) \\`