Question

what is the external net force exerted on a 3.5 kg papaya, which is being pushed across a table and has an acceleration of 2.2 m /s² to the left​

Answer 1

F = 7.7 [N]

Step-by-step explanation:

In order to solve this problem, we must use Newton's second law, which tells us that the sum of forces on a body is equal to the product of mass by acceleration.

ΣF = m*a

where:

m = mass = 3.5 [kg]

a = acceleration = 2.2 [m/s^2]

F = (3.5*2.2) = 7.7 [N]