Question

Determine if the function f(x)=x3+x is even, odd, or neither.

Answer 1

Even

Explanation:

Let x be any real number,

We know that the cubes of odd and even numbers are odds and evens respectively....

Hence,

If x was odd then,

`f(Odd)=(Odd)^3+Odd\\f(Odd)=Odd+Odd\\f(Odd)= Even`

If x was even then,

`f(even)=(even)^3+even\\f(even)=even+even\\f(even)=even`