![\tt Step-by-step~explanation:](https://img.qammunity.org/2021/formulas/mathematics/middle-school/1yvv69zlhkbxhn4v3cihgxbj4z92s81wn4.png)
When we solve for x, we have to move all the numbers that do not contain the variable on one side, and keep x on the other side. In other words, we have to isolate the variable.
![\tt Step~1:](https://img.qammunity.org/2021/formulas/mathematics/high-school/td6u35j3gyzkyxq2z12ex68fup5boe9d1z.png)
Equation: 9x + 28 = 5 (x + 8)
Using PEMDAS*, we will distribute the 5 to x + 8.
![\tt 5(x+8)\\5x+40\\9x+28=5x+40](https://img.qammunity.org/2021/formulas/mathematics/high-school/jmvutrei2fr0ryb09orj7byrhnpdys9ff5.png)
![\tt Step~2:](https://img.qammunity.org/2021/formulas/mathematics/high-school/42ystigthi5jraeckxqu1502a0bp41zkf4.png)
Then, let's subtract 28 from the left side of the equation to cancel the 28, then do the same thing on the right side.
![\tt 9x+28(-28)^(**)=5x+40(-28)^(**)\\9x=5x+12](https://img.qammunity.org/2021/formulas/mathematics/high-school/7bgnep02lh4uzrju3xndfoqt2m4lt2q4u4.png)
![\tt Step~3:](https://img.qammunity.org/2021/formulas/mathematics/high-school/kzruw8vgkxq6egm586l6dq1nvmb5gemz22.png)
Subtract 5x from both sides to bring it to the left side of the equation.
![\tt 9x(-5x)=5x(-5x)+12\\4x=12](https://img.qammunity.org/2021/formulas/mathematics/high-school/qpl938c2uvcf1v1lr3q005kxwxvgiuc69p.png)
![\tt Step~4:](https://img.qammunity.org/2021/formulas/mathematics/high-school/fsvy83yxq1bojhsczq84veekvc0yfp7chw.png)
Finally, we can divide both sides by 4 to get x by itself.
![\tt (4x)/(4) =x\\(12)/(4)=3\\ x=3](https://img.qammunity.org/2021/formulas/mathematics/high-school/eh3vywgmv8dsouszzyabz1h3rhl9ads73x.png)
![\large\boxed{\tt Our~final~answer:~x=3}](https://img.qammunity.org/2021/formulas/mathematics/high-school/87gt52sipmaskzt6bsg3a2ey4u52ymn29y.png)
*PEMDAS + Parentheses first, then Exponents, then Multiplication/Division, and finally Addition/Subtraction.
**The numbers in parentheses here tell you to ADD/SUBTRACT, not multiply.