Question

A student is standing on a very steep hill, kicks a soccer ball horizontally with a speed of 15 m/s toward a student who is sitting on a level field 9.8 meters below. How long does it take the soccer ball to strike the ground? If the second student catches the soccer ball at ground level, how far from the hill was she?

Answer 1

The time is 0.65 sec.

The distance from the hill is 2.07 m.

Step-by-step explanation:

Given that,

Speed = 15 m/s

Distance = 9.8 m

Along horizontal,

We need to calculate the time

Using formula of time

`t=(d)/(v)`

Where, d =distance

v = velocity

Put the value into the formula

`t=(9.8)/(15)`

`t=0.65\ sec`

Along vertical,

We need to calculate the height

Using equation of motion

`s=ut+(1)/(2)gt^2`

Put the value in the equation

`s=0+(1)/(2)*9.8*(0.65)^2`

`s=2.07\ m`

Hence, The time is 0.65 sec.

The distance from the hill is 2.07 m.