Question

A car goes from 4.47 m/s to 17.9 m/s in 3 seconds. calculate the acceleration of the car

Answer 1

4.48 m/s²

Step-by-step explanation:

Acceleration is change in velocity over time.

a = Δv / Δt

a = (17.9 m/s − 4.47 m/s) / 3 s

a = 4.48 m/s²

Answer 2

`\boxed {\tt a \approx4.48 \ m/s^2}`

Step-by-step explanation:

Acceleration can be found by dividing the change in velocity over the time.

`a=(\Delta v)/(t)`

The change in velocity can be found by subtracting the final velocity by the initial velocity.

`\Delta v= final \ velocity - initial \ velocity`

The final velocity is 17.9 meters per second.

The initial velocity is 4.47 meters per second.

`\Delta v=17.9 \ m/s-4.47 \ m/s`

`\Delta v=13.43 \ m/s`

The change in velocity is 13.43 meters per second and the time is 3 seconds.

`a=(13.43 \ m/s)/(3 \ s)`

Divide.

`a=4.47666667 \ m/s^2`

`a \approx4.48 \ m/s^2`

The acceleration is about 4.48 meters per seconds squared.