Question

Please help if you can! :)

Answer 1

B

Explanation:

We have the function:

`f(x)=x^2-5x`

And we are given that:

`f(n)=-4`

And we want to find the value of n such that this is true.

So, let's substitute f(x) for -4 and x for n. This yields:

`-4=n^2-5n`

Let's solve for n. First, add 4 to both sides:

`n^2-5n+4=0`

This is a quadratic. We can solve by factoring:

`(n-1)(n-4)=0`

Zero Product Property:

`n-1=0\text{ or } n-4=0`

Solve for n for each equation:

`n=1\text{ or }n=4`

So, n can be either 1 or 4.

Our of our answer choices, the correct answer is B.

And we're done!