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During a school tournament, Team A had 10 of its 12 team members present.

Team B had 13 of its 15 players present.
Which team had the lesser percent of its team present at the tournament?

User GPH
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1 Answer

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Answer:

Team A.

Explanation:

We know that Team A had 10 of its 12 members present.

We can write this as the following fraction:


A=10/12

We can convert this to a decimal by dividing the two numbers. Use a calculator:


A\approx.8333

And we can convert this to a percent by moving the decimal too places to the right and by adding a percent sign:


A\approx83.33\%

So, about 83.33% of members on Team A was present.

We know that Team B had 13 of its 15 members present.

We can write this as the following fraction:


B=13/15

Again, we can convert this to a decimal by dividing the two numbers:


B\approx 0.8667

Change this to a percent:


B\approx86.67\%

So, Team A had a participation rate of 83.33% while Team B had a participation rate of 86.67%.

So, the team that had the lesser percent of the team present at the tournament is Team A.

And we're done!

User AarCee
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