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Use sigma notation to represent the sum of the first eight terms of the following sequence: 4, 7, 10, …

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2 votes

Answer:


\displaystyle \boxed{ \sum_(k=1)^(8) (1+3k) }

Explanation:

Hello,

We are looking for something like


\displaystyle \sum_(k=1)^(8) u_k

where


u_1=4\\ \\u_2=7 \\ \\u_3 =10 \\ \\u_k=1+3k

So,


\displaystyle \sum_(k=1)^(8) u_k=\sum_(k=1)^(8) (1+3k)\\\\=\sum_(k=1)^(8) (1)+3\sum_(k=1)^(8) (k)\\\\=8+3* (9*8)/(2)\\ \\=8+108=116

Thanks

User MMALSELEK
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