Question

Find the sum of the first 6 terms of the following series, to the nearest integer. 15 , 5 , 5/3

Answer 1

22

Explanation:

the pattern here is to divide the previous number by 3

the first number is 15, divided by 3 to give you the second number:5 ,the second number divided by 3 gives us 5/3

using that principle the first six terms are :

15, 3, 5/3 , 5/9, 5/27, 5/81

(just multiply the denominator by 3)

adding we have

`15 + 5 + (5)/(3) + (5)/(9) + (5)/(27) + (5)/(81) = (1820)/(81)`

1820/81 in decimal is 22.4691 to the nearest whole number that is 22.

hope this helps!