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Simplify- 4c^2-36/8c^2-24c/12c+36/2c^2-6c
pls help :)

Simplify- 4c^2-36/8c^2-24c/12c+36/2c^2-6c pls help :)-example-1
User Seemly
by
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2 Answers

21 votes
21 votes

Answer:

d

Explanation:

separate the 2 divisions and simplify each , that is


(4c^2-36)/(8c^2-24c) ← factor numerator/ denominator

=
(4(c^2-9))/(8c(c-3)) ← factor difference of squares on numerator

=
(4(c-3)(c+3))/(8c(c-3)) ← cancel (c - 3) and 4/8 on numerator/ denominator

=
(c+3)/(2c)

---------------------------------------------------


(12c+36)/(2c^2-6c) ← factor numerator/ denominator

=
(12(c+3))/(2c(c-3)) ← cancel 12 and 2 on numerator/ denominator

=
(6(c+3))/(c(c-3))

----------------------------------------------------------

to divide the top fraction by the lower fraction

leave top fraction, change division to multiplication, turn lower fraction upside down.


(c+3)/(2c) ×
(c(c-3))/(6(c+3)) ← cancel (c + 3) and c on numerator/ denominator

=
(c-3)/(2(6))

=
(c-3)/(12) → d

User Kkoehne
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7 votes
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\displaystyle ((4c^2-36)/(8c^2-24c))/((12c+36)/(2c^2 -6c))\\\\\\=\left((4c^2 -36)/(8c^2 -24c)\right) \cdot \left((2c^2 -6c)/(12c+36)\right)\\\\\\=\left[(4(c^2 -9))/(8(c^2-3))\right]\cdot\left[(2(c^2-3))/(12(c+3))\right]\\\\\\=(8(c^2-3^2))/(8 \cdot 12(c+3))\\\\\\=((c+3)(c-3))/(12(c+3))\\\\\\=(c-3)/(12)


\text{Hence the answer is d.}

User Dnickels
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