Question

a car travelling east a constant speed of 20 metre per second be constructed at 3.8 metre per second square when it is 200 behind currently moving East at a constant speed of 2 metre per second how long will it take for the car to catch up with the truck how far will it truck and car travel during this time​

Answer 1

Let, after t minutes car catch up with truck.

So, distance covered by car is, d = 200 + 2t.

Acceleration of car is, a = 2 m/s².

Initial velocity, u = 20 m/s.

Now, by equation of motion :

`s =ut+(at^2)/(2)`

`200+2t = 20t + (2t^2)/(2)\\\\t^2+18t -200=0`

`t=(-18\pm√(18^2-4(1)(-200)))/(2)\\\\t = (-18\pm33.53)/(2)\\\\t=7.765\ s`( eliminating negative solution )

Therefore, time required is 7.765 s.