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What is the distance covered by a free falling body during the first 3 seconds of its motion? ANSWER MY QUESTION WITH EXPLANATION ​
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What is the distance covered by a free falling body during the first 3 seconds of its motion?

ANSWER MY QUESTION WITH EXPLANATION ​

User Funkenstrahlen
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1 Answer

6 votes
Distance s=ut+1/2 at^2
If it’s released then this becomes
s=1/2at^2
s=1/2 *9.81*9
s=44.1 m
User Nightloewe
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