Answer:
12 red balls
4 yellow balls
2 blue balls
2 green balls
Explanation:
set no. of yellow, blue, red and green ball as y, b, r, g respectively
y=2b
r=3y
g=b
y+b+r+g = 20 (translate all of them into b (smallest in qty)
2b + b + 3(2b) + b = 20
10b = 20
b =2
y = 4, r = 12, b =2, g =2