Question

Solve for x ~


`\bold\pink{x {}^(2) + 5x - 6 = 0}`

ty! ._.

Answer 1

`\qquad \qquad \rm \large \dag \: Answer \: \dag`

We have been given a Quadratic equation, where we have to find the real values of x ~

So, let's proceed with middle term splitting method :

`\qquad \sf  \dashrightarrow \: {x}^(2) + 5x - 6 = 0`

`\qquad \sf  \dashrightarrow \: x {}^(2) + 6x - x - 6 = 0`

`\qquad \sf  \dashrightarrow \: {x(}^{} x + 6) - 1(x + 6) = 0`

`\qquad \sf  \dashrightarrow \: (x + 6)(x - 1) = 0`

Now, we have two conditions here~

Either (x + 6) = 0

`\qquad \sf  \dashrightarrow \: x = - 6`

or (x - 1) = 0

`\qquad \sf  \dashrightarrow \: x = 1`