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The temperature on a February moming is -6° Celsius at 6 am. If the temperature drops 2 degrees by 7 am, rises 3 degrees between 7 am and 8 a.m.

and then drops 9 degrees between 8 am and 9 am, find the temperature at 9 am

User Philoniare
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2 Answers

6 votes
-6 - 2 = -8
-8 + 3 = -5
-5 - 9 = -14

the temperature at 9am would be -14°C .
User Jochen Ritzel
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2 votes

Answer:

-24degC

Explanation:

-6degC dropping by 2degC leads to -8degC (2degC colder, higher value negative numbers are colder as negative numbers increase in the opposite direction of positives)

so next -8degC rising by 3degC which is 3degC hotter(less negative) will give -5degC

the finap drop by 9degC makes the final temperature -5 -19 = -24degC(similar reasoning)

if you want a more straightforward method to doing these sorts of questions, just take temperature rise : add the value it rose by and temperature fall/drop: subtract the value it dropped/falled by.

User Gustavo Bissolli
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