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What is the solution of startroot x 12 endroot = x?

User Casademora
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1 Answer

5 votes

Answer:

x = 0 ; x = 1

Explanation:


\sqrt{x^(12)} =x


\Longleftrightarrow \sqrt{x^(6* 2)} =x


\Longleftrightarrow \sqrt{\left( x^(6)\right)^(2) } =x


\Longleftrightarrow |x^(6)|=x


\Longleftrightarrow x^(6)=x\ \ \ ;\ |x^(6)|=x^(6)


\Longleftrightarrow x^(6)-x=0


\Longleftrightarrow x(x^(5)-1)=0


\Longleftrightarrow x=0 \ \ or\ \ (x^(5)-1)=0


\Longleftrightarrow x=0\ \ or\ \ x^(5)=1


\Longleftrightarrow x=0\ \ or\ \ x=1

User Caddisfly
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