Question

Determine the volume of an 85-gram sample of gold at ST
M

Answer 1

Volume of gold is 9.64 L .

Explanation:

Given data:

Mass of gold = 85 g

Temperature = standard = 273 K

Pressure = standard = 1 atm

Volume of gold = ?

Solution:

The given problem will be solve by using general gas equation,

PV = nRT

P= Pressure

V = volume

n = number of moles

R = general gas constant = 0.0821 atm.L/ mol.K

T = temperature in kelvin

Now we will calculate the number of moles of gold.

Number of moles = mass/molar mass

Number of moles = 85 g/ 197 g/mol

Number of moles = 0.43

1 atm × V = 0.43 mol ×0.0821 atm.L/ mol.K × 273 K

V = 9.64 atm.L / 1 atm

V = 9.64 L