Answer:
The answer is 14.29 %
Step-by-step explanation:
The percentage error of a certain measurement can be found by using the formula
![P(\%) = (error)/(actual \: \: number) * 100\% \\](https://img.qammunity.org/2021/formulas/chemistry/high-school/q0zosffwg85xn9jdfzfbo353sezuv4qp22.png)
From the question
actual density = 0.70 g/mL
error = 0.8 - 0.7 = 0.1
So we have
![P(\%) = (0.1)/(0.7) * 100 \\ = 14.285714...](https://img.qammunity.org/2021/formulas/chemistry/high-school/sozbsy43tjsnuuj1i9aserlow2kxw6tvl8.png)
We have the final answer as
14.29 %
Hope this helps you