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If the observed value for a density is 0.80 g/mL and the accepted value is 0.70 g/mL what is the percent error?

User Hermes
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1 Answer

6 votes

Answer:

The answer is 14.29 %

Step-by-step explanation:

The percentage error of a certain measurement can be found by using the formula


P(\%) = (error)/(actual \: \: number) * 100\% \\

From the question

actual density = 0.70 g/mL

error = 0.8 - 0.7 = 0.1

So we have


P(\%) = (0.1)/(0.7) * 100 \\ = 14.285714...

We have the final answer as

14.29 %

Hope this helps you

User Barkles
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5.4k points