Question

I got CONFUSED PLZ HELP?

Answer 1

`x = √(48) \\\\x = √(63) \\\\x = \sqrt[3]{73}`

Explanation:

`x^2 = 48\\x^2 = 63\\x^3 = 73`

Solve for x

Equation 1 ;

`x^2 =48\\\\Square\:root\:both\:sides\\\\√(x^2) =√(48) \\\\Simplified \:form;\\x =4√(3)`

Equation 2;

`x^2 =63\\\\Square\:root\:both\:sides\\\\√(x^2) =√(63) \\\\Simplified \:form;\\x =3√(7)`

Equation 3 ;

`x^3 =73\\\\Cube\:root\:both\:sides\\\\\sqrt[3]{x^3}= \sqrt[3]{73} \\\\x = \sqrt[3]{73}`

Answer 2

A, B, F

Explanation:

To solve this, you look at the powers of x and take either the square root (if it is to a power of 2) or the cube root (if a power of 3) of both sides to isolate x. For the first equation, you take the square root of 48, so A is correct. For the second one, you take the square root of 63, so B is correct. For the final equation, you take the cube root of 73, so F is correct.